vdo_waitq_dequeue_waiter(9)

✨ NAME ✨

bestie, welcome to the Kernel API Manual entry for vdo_waitq_dequeue_waiter(9) 💅 — this one literally removes the first (oldest) waiter from a waitq. like, the oldest one, no cap 🫶

🎀 SYNOPSIS 🎀

okay so the signature is giving:

struct vdo_waiter * vdo_waitq_dequeue_waiter (struct vdo_wait_queue
*waitq );

💖 ARGUMENTS 💖

• waitq — the vdo_wait_queue from which to remove the first entry. that's the whole vibe ✨

🌸 DESCRIPTION 🌸

so after this, you're on wake-up duty: the caller will be responsible for waking the waiter by continuing its execution appropriately. periodt 💅 no cap, that part is the caller's main character energy 😭

🦋 RETURN 🦋

it returns the first (oldest) waiter in the waitq, or NULL if the waitq is empty. slay 🌈 if it's empty, you get NULL, fr fr.

🔥 SEE ALSO 🔥

go check these besties too, iykyk:

• the kernel file: ./drivers/md/dm-vdo/wait-queue.c ✨
• vdo_waitq_enqueue_waiter(9)
• vdo_waitq_transfer_all_waiters(9)
• vdo_waitq_notify_all_waiters(9)
• vdo_waitq_get_first_waiter(9)
• vdo_waitq_dequeue_matching_waiters(9)
• vdo_waitq_notify_next_waiter(9)

byeee 🫶 source/version: ./drivers/md/dm-vdo, date: October 2026, page: vdo_waitq_dequeue_waiter(9) — mwah 💋