std::set_union(3)
π std::set_union(3) β NAME π
okay bestie, welcome to std::set_union(3) from the C++ Standard Library. Yes, this is the sorted-union algorithm, and it is literally iconic. The name is std::set_union β std::set_union.
β¨ SYNOPSIS β¨
Defined in header <algorithm>.
template< class InputIt1, class InputIt2, class OutputIt >
OutputIt set_union( InputIt1 first1, InputIt1 last1,
InputIt2 first2, InputIt2 last2,
OutputIt d_first );
(1)βconstexpr since C++20.
template< class ExecutionPolicy,
class ForwardIt1, class ForwardIt2, class ForwardIt3 >
ForwardIt3 set_union( ExecutionPolicy&& policy,
ForwardIt1 first1, ForwardIt1 last1,
ForwardIt2 first2, ForwardIt2 last2,
ForwardIt3 d_first );
(2)βsince C++17.
template< class InputIt1, class InputIt2,
class OutputIt, class Compare >
OutputIt set_union( InputIt1 first1, InputIt1 last1,
InputIt2 first2, InputIt2 last2,
OutputIt d_first, Compare comp );
(3)βconstexpr since C++20.
template< class ExecutionPolicy,
class ForwardIt1, class ForwardIt2,
class ForwardIt3, class Compare >
ForwardIt3 set_union( ExecutionPolicy&& policy,
ForwardIt1 first1, ForwardIt1 last1,
ForwardIt2 first2, ForwardIt2 last2,
ForwardIt3 d_first, Compare comp );
(4)βsince C++17.
Constructs a sorted union beginning at d_first consisting of the set of elements present in one or both sorted ranges [first1, last1) and [first2, last2).
If [first1, last1) contains m elements that are equivalent to each other and [first2, last2) contains n elements that are equivalent to them, then all m elements will be copied from [first1, last1) to the output range, preserving order, and then the final std::max(n - m, 0) elements will be copied from [first2, last2) to the output range, also preserving order.
- 1) If
[first1, last1)or[first2, last2)is not sorted with respect tooperator<(until C++20) orstd::less{}(since C++20), the behavior is undefined. - 3) If
[first1, last1)or[first2, last2)is not sorted with respect tocomp, the behavior is undefined. - 2,4) Same as
(1,3), but executed according topolicy. These overloads participate in overload resolution only ifstd::is_execution_policy_v<std::decay_t<ExecutionPolicy>>istrue(until C++20) orstd::is_execution_policy_v<std::remove_cvref_t<ExecutionPolicy>>istrue(since C++20).
If the output range overlaps with[first1, last1)or[first2, last2), the behavior is undefined. Like, do not do that, bestie. π
πΈ PARAMETERS πΈ
first1,last1β the first input sorted range.first2,last2β the second input sorted range.d_firstβ the beginning of the output range.policyβ the execution policy to use. See execution policy for details.compβ comparison function object (i.e. an object that satisfies the requirements ofCompare) which returnstrueif the first argument is less than (i.e. is ordered before) the second.
The signature of the comparison function should be equivalent to the following:
bool cmp(const Type1& a, const Type2& b);
While the signature does not need to have const&, the function must not modify the objects passed to it and must be able to accept all values of type (possibly const) Type1 and Type2 regardless of value category (thus, Type1& is not allowed, nor is Type1 unless for Type1 a move is equivalent to a copy (since C++11)). The types Type1 and Type2 must be such that objects of types InputIt1 and InputIt2 can be dereferenced and then implicitly converted to both Type1 and Type2.
π¦ TYPE REQUIREMENTS π¦
InputIt1,InputIt2must meet the requirements ofLegacyInputIterator.ForwardIt1,ForwardIt2,ForwardIt3must meet the requirements ofLegacyForwardIterator.OutputItmust meet the requirements ofLegacyOutputIterator.Comparemust meet the requirements ofCompare.
π RETURN VALUE π
Iterator past the end of the constructed range. That's it. That's the return. π«Ά
π COMPLEXITY π
Given N_1 as std::distance(first1, last1) and N_2 as std::distance(first2, last2):
- 1,2) At most
2 \cdot (N_1+N_2)-1comparisons usingoperator<(until C++20) orstd::less{}(since C++20). - 3,4) At most
2 \cdot (N_1+N_2)-1applications of the comparison functioncomp.
π EXCEPTIONS π
The overloads with a template parameter named ExecutionPolicy report errors as follows:
- If execution of a function invoked as part of the algorithm throws an exception and
ExecutionPolicyis one of the standard policies,std::terminateis called. For any otherExecutionPolicy, the behavior is implementation-defined. - If the algorithm fails to allocate memory,
std::bad_allocis thrown.
π§ POSSIBLE IMPLEMENTATION π§
Here's the vibe in code, bestie:
set_union (1)
template<class InputIt1, class InputIt2, class OutputIt>
OutputIt set_union(InputIt1 first1, InputIt1 last1,
InputIt2 first2, InputIt2 last2, OutputIt d_first)
{
for (; first1 != last1; ++d_first)
{
if (first2 == last2)
return std::copy(first1, last1, d_first);
if (*first2 < *first1)
*d_first = *first2++;
else
{
*d_first = *first1;
if (!(*first1 < *first2))
++first2;
++first1;
}
}
return std::copy(first2, last2, d_first);
}
set_union (3)
template<class InputIt1, class InputIt2, class OutputIt, class Compare>
OutputIt set_union(InputIt1 first1, InputIt1 last1,
InputIt2 first2, InputIt2 last2, OutputIt d_first, Compare comp)
{
for (; first1 != last1; ++d_first)
{
if (first2 == last2)
// Finished range 2, include the rest of range 1:
return std::copy(first1, last1, d_first);
if (comp(*first2, *first1))
*d_first = *first2++;
else
{
*d_first = *first1;
if (!comp(*first1, *first2)) // Equivalent => don't need to include *first2.
++first2;
++first1;
}
}
// Finished range 1, include the rest of range 2:
return std::copy(first2, last2, d_first);
}
π NOTES π
This algorithm performs a similar task as std::merge does. Both consume two sorted input ranges and produce a sorted output with elements from both inputs. The difference between these two algorithms is with handling values from both input ranges which compare equivalent (see notes on LessThanComparable). If any equivalent values appeared n times in the first range and m times in the second, std::merge would output all n + m occurrences whereas std::set_union would output std::max(n, m) ones only. So std::merge outputs exactly std::distance(first1, last1) + std::distance(first2, last2) values and std::set_union may produce fewer.
π EXAMPLE π
#include <algorithm>
#include <iostream>
#include <iterator>
#include <vector>
void println(const std::vector<int>& v)
{
for (int i : v)
std::cout << i << ' ';
std::cout << '\n';
}
int main()
{
std::vector<int> v1, v2, dest;
v1 = {1, 2, 3, 4, 5};
v2 = {3, 4, 5, 6, 7};
std::set_union(v1.cbegin(), v1.cend(),
v2.cbegin(), v2.cend(),
std::back_inserter(dest));
println(dest);
dest.clear();
v1 = {1, 2, 3, 4, 5, 5, 5};
v2 = {3, 4, 5, 6, 7};
std::set_union(v1.cbegin(), v1.cend(),
v2.cbegin(), v2.cend(),
std::back_inserter(dest));
println(dest);
}
π¨οΈ Output π¨οΈ
1 2 3 4 5 6 7
1 2 3 4 5 5 5 6 7
π DEFECT REPORTS π
The following behavior-changing defect reports were applied retroactively to previously published C++ standards.
LWG 291β Applied to C++98. Behavior as published: it was unspecified how to handle equivalent elements in the input ranges. Correct behavior: specified.
π SEE ALSO π
includesβ returnstrueif one sequence is a subsequence of another (function template).mergeβ merges two sorted ranges (function template).set_differenceβ computes the difference between two sets (function template).set_intersectionβ computes the intersection of two sets (function template).set_symmetric_differenceβ computes the symmetric difference between two sets (function template).ranges::set_union(C++20)β computes the union of two sets (niebloid).
xoxo, your Unix bestie π β source: http://cppreference.com, version/date: 2024.06.10, and the page is std::set_union(3). Slay. β¨
π¦ where this page comes from
- nixpkgs unstable: stdman 2024.07.05
- opensuse-leap 16.0: stdman 2024.07.05-bp160.1.9 Β· MIT
- π girlified by deepseek-ai/DeepSeek-V4.1-Flash-1017 on : a language model's rewrite of the original, under its terms