std::isunordered(3)

πŸ“¦ version 2024.07.05, in nixpkgs unstable, opensuse-leap 16.0

okay so bestie, welcome to std::isunordered(3) πŸ’… this is the C++ Standard Libary page for the function that tells you when two floating-point numbers are unordered β€” meaning one or both are NaN and literally cannot be meaningfully compared with each other. it's giving chaos-detector energy, no cap πŸ¦‹

πŸ’– NAME

  • std::isunordered β€” std::isunordered (yes, the name ate and left no crumbs πŸ’…)

✨ Synopsis

Defined in header <cmath>:

  • bool isunordered( float x, float y ); β€” (since C++11)
  • bool isunordered( double x, double y ); β€” (until C++23)
  • bool isunordered( long double x, long double y );
  • constexpr bool isunordered( /* floating-point-type */ x, /* floating-point-type */ y ); β€” (1) (since C++23)

Additional overloads 🌸

Defined in header <cmath>:

  • template< class Arithmetic1, class Arithmetic2 > bool isunordered( Arithmetic1 x, Arithmetic2 y ); β€” (A) (since C++11) (constexpr since C++23)

The tea β˜•

1) Determines if the floating point numbers x and y are unordered, that is, one or both are NaN and thus cannot be meaningfully compared with each other. periodt πŸ’…

The library provides overloads for all cv-unqualified floating-point types as the type of the parameters x and y. (since C++23)

A) Additional overloads are provided for all other combinations of arithmetic types. 🫢

πŸŽ€ Parameters

  • x, y β€” floating-point or integer values πŸ’–

🫢 Return value

true if either x or y is NaN, false otherwise. periodt.

🧚 Notes

okay so the additional overloads are not required to be provided exactly as (A). They only need to be sufficient to ensure that, for their first argument num1 and second argument num2:

  • If num1 or num2 has type long double, then std::isunordered(num1, num2) has the same effect as std::isunordered(static_cast<long double>(num1), static_cast<long double>(num2)).
  • Otherwise, if num1 and/or num2 has type double or an integer type, then std::isunordered(num1, num2) has the same effect as (until C++23) std::isunordered(static_cast<double>(num1), static_cast<double>(num2)).
  • Otherwise, if num1 or num2 has type float, then std::isunordered(num1, num2) has the same effect as std::isunordered(static_cast<float>(num1), static_cast<float>(num2)).

If num1 and num2 have arithmetic types, then std::isunordered(num1, num2) has the same effect as std::isunordered(static_cast</* common-floating-point-type */>(num1), static_cast</* common-floating-point-type */>(num2)), where /* common-floating-point-type */ is the floating-point type with the greatest floating-point conversion rank and greatest floating-point conversion subrank between the types of num1 and num2, (since C++23) arguments of integer type are considered to have the same floating-point conversion rank as double.

If no such floating-point type with the greatest rank and subrank exists, then overload resolution does not result in a usable candidate from the overloads provided. πŸ’€

πŸ”₯ Example

Run this code, bestie:

#include <cmath>
#include <iostream>

#define SHOW_UNORDERED(x, y) \
    std::cout << std::boolalpha << "isunordered(" \
              << #x << ", " << #y << "): " \
              << std::isunordered(x, y) << '\n'

int main()
{
    SHOW_UNORDERED(10, 01);
    SHOW_UNORDERED(INFINITY, NAN);
    SHOW_UNORDERED(INFINITY, INFINITY);
    SHOW_UNORDERED(NAN, NAN);
}

🌈 Output

isunordered(10, 01): false
isunordered(INFINITY, NAN): true
isunordered(INFINITY, INFINITY): false
isunordered(NAN, NAN): true

πŸ‘‘ See also

  • fpclassify β€” categorizes the given floating-point value (C++11) (function)
  • isnan β€” checks if the given number is NaN (C++11) (function)
  • C documentation for isunordered

source/version: http://cppreference.com Β· date: 2024.06.10 Β· page: std::isunordered(3) β€” bye bestie, go check your NaNs πŸ’–βœ¨πŸ¦‹

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