std::chrono...operatorint(3)

💅 std::chrono...operatorint(3) 💅

okay so bestie, this is a page from the C++ Standard Libary manual, and the main character is std::chrono::year::operatorint(3). Yes, the title is a whole vibe, but the plot is simple: std::chrono::year can give you its year value as an int. 🎀

✨ NAME ✨

std::chrono::year::operatorint — literally the conversion operator that returns the year value stored in *this. No cap. 💖

🌸 Synopsis 🌸

constexpr explicit operator int() const noexcept;  (since C++20)

Returns the year value stored in *this. (That's the whole little arc, and it ate. 👑)

🎀 Return value 🎀

The year value stored in *this. That's it, that's the tea. 🍓

🦋 Example 🦋

       // Run this code

        #include <chrono>
        #include <iostream>
        using namespace std::chrono;

        int main()
        {
            constexpr std::chrono::year y{2020};
            std::cout << "The year is: " << static_cast<int>(y) << '\n';

            const year_month_day ymd{floor<days>(system_clock::now())};
            const std::chrono::year this_year{ymd.year()};
            std::cout << "This year is: " << int(this_year) << '\n';
        }

🍓 Possible output 🍓

The year is: 2020
This year is: 2023

later bestie — this iconic page is from http://cppreference.com, dated 2024.06.10, and filed under std::chrono...operatorint(3). mwah 💋