std::accumulate(3)
π std::accumulate(3) π
okay bestie, welcome to std::accumulate β a.k.a. the C++ Standard Library function that lives in std::accumulate(3) land and just... adds stuff up for you. that's it. that's the vibe. she folds, she sums, she does it in order, and she's iconic for it π«Ά
β¨ Synopsis β¨
first things first, she's Defined in header <numeric> β don't forget to include her or she'll ghost you π
template< class InputIt, class T > (1)
(constexpr since C++20)
T accumulate( InputIt first, InputIt last, T init );
template< class InputIt, class T, class BinaryOp >
T accumulate( InputIt first, InputIt last, T init, (2)
(constexpr since C++20)
BinaryOp op );
so what does she actually do? she computes the sum of the given value init and the elements in the range [first, last). literally that's the whole thing π
- (1) β initializes the accumulator
acc(of typeT) with the initial valueinitand then modifies it with
acc = acc + *i
(until C++20)
acc = std::move(acc) + *i
(since C++20)
for every iterator i in the range [first, last) in order. no skipping, no shuffling, in order fr fr.
- (2) β same deal, initializes the accumulator
acc(of typeT) with the initial valueinitand then modifies it with
acc = op(acc, *i)
(until C++20)
acc = op(std::move(acc), *i)
(since C++20)
for every iterator i in the range [first, last) in order.
π GIRL. WARNING. if any of the following conditions is satisfied, the behavior is undefined β and undefined is not cute, undefined is chaos: -Tis not CopyConstructible. -Tis not CopyAssignable. -opmodifies any element of[first, last). -opinvalidates any iterator or subrange in[first, last].
like bestie... just don't. π©
πΈ Parameters πΈ
first,lastβ the range of elements to sum π§initβ initial value of the sumopβ binary operation function object that will be applied.
the signature of the function should be equivalent to the following:
Ret fun(const Type1 &a, const Type2 &b);
okay so about op, here's the tea β β the signature does not need to have const &. The type Type1 must be such that an object of type T can be implicitly converted to Type1. The type Type2 must be such that an object of type InputIt can be dereferenced and then implicitly converted to Type2. The type Ret must be such that an object of type T can be assigned a value of type Ret. no cap, that's the whole requirement bestie π
π¦ Type requirements π¦
InputItmust meet the requirements of LegacyInputIterator.
β Return value β
acc after all modifications. yes queen, the final accumulator, that's her, main character energy π
π Possible implementation π
accumulate (1)
template<class InputIt, class T>
constexpr // since C++20
T accumulate(InputIt first, InputIt last, T init)
{
for (; first != last; ++first)
init = std::move(init) + *first; // std::move since C++20
return init;
}
accumulate (2)
template<class InputIt, class T, class BinaryOperation>
constexpr // since C++20
T accumulate(InputIt first, InputIt last, T init, BinaryOperation op)
{
for (; first != last; ++first)
init = op(std::move(init), *first); // std::move since C++20
return init;
}
π§ Notes π§
std::accumulate performs a left fold. so if you're sitting there like "okay but what if I want a right fold" β you gotta reverse the order of the arguments to the binary operator, and use reverse iterators. iykyk π
and this next part is the classic trap, so listen up π: if left to type inference, op operates on values of the same type as init which can result in unwanted casting of the iterator elements. for example:
std::accumulate(v.begin(), v.end(), 0)
likely does not give the result one wishes for when v is of type std::vector<double>. yeah. she's summing doubles into an int accumulator. tragic. don't do that to yourself π
π Example π
// Run this code
#include <functional>
#include <iostream>
#include <numeric>
#include <string>
#include <vector>
int main()
{
std::vector<int> v{1, 2, 3, 4, 5, 6, 7, 8, 9, 10};
int sum = std::accumulate(v.begin(), v.end(), 0);
int product = std::accumulate(v.begin(), v.end(), 1, std::multiplies<int>());
auto dash_fold = [](std::string a, int b)
{
return std::move(a) + '-' + std::to_string(b);
};
std::string s = std::accumulate(std::next(v.begin()), v.end(),
std::to_string(v[0]), // start with first element
dash_fold);
// Right fold using reverse iterators
std::string rs = std::accumulate(std::next(v.rbegin()), v.rend(),
std::to_string(v.back()), // start with last element
dash_fold);
std::cout << "sum: " << sum << '\n'
<< "product: " << product << '\n'
<< "dash-separated string: " << s << '\n'
<< "dash-separated string (right-folded): " << rs << '\n';
}
Output:
sum: 55
product: 3628800
dash-separated string: 1-2-3-4-5-6-7-8-9-10
dash-separated string (right-folded): 10-9-8-7-6-5-4-3-2-1
like?? the dash-separated string ATE. both directions. obsessed π₯
π Defect reports π
the following behavior-changing defect reports were applied retroactively to previously published C++ standards. yes, they went back and fixed the past, we love a glow-up β¨
- LWG 242 β Applied to
C++98. Behavior as published:opcould not have side effects. Correct behavior: it cannot modify the ranges involved. - LWG 2055 (P0616R0) β Applied to
C++20. Behavior as published:accwas not moved while being accumulated. Correct behavior: it is moved.
π See also π
adjacent_differenceβ computes the differences between adjacent elements in a range (function template)inner_productβ computes the inner product of two ranges of elements (function template)partial_sumβ computes the partial sum of a range of elements (function template)reduce(C++17)β similar tostd::accumulate, except out of order (function template)ranges::fold_left(C++23)β left-folds a range of elements (niebloid)
okay that's the whole page bestie, go forth and fold π π¦
source: http://cppreference.com β version 2024.06.10 β and this lil std::accumulate(3) page was last touched on that date π mwah, ily, go sum something π
π¦ where this page comes from
- nixpkgs unstable: stdman 2024.07.05
- opensuse-leap 16.0: stdman 2024.07.05-bp160.1.9 Β· MIT
- π girlified by deepseek-ai/DeepSeek-V4.1-Flash-1017 on : a language model's rewrite of the original, under its terms