SRC/zspsv.f(3)
π SRC/zspsv.f β from the Library Functions Manual β¨
okay bestie, sit down, because this one is a whole moment. This is SRC/zspsv.f, straight out of the Library Functions Manual, and it's about to solve your linear system AND your skin routine. π§ββοΈ
β¨ SYNOPSIS β¨
π Functions/Subroutines
subroutine zspsv (uplo, n, nrhs, ap, ipiv, b, ldb, info)β ZSPSV computes the solution to system of linear equationsA * X = Bfor OTHER matrices
π«Ά Function/Subroutine Documentation
subroutine zspsv (character uplo, integer n, integer nrhs, complex*16,
dimension( * ) ap, integer, dimension( * ) ipiv, complex*16, dimension(
ldb, * ) b, integer ldb, integer info)
ZSPSV computes the solution to system of linear equations A * X = B for OTHER matrices. slay. π
πΈ Purpose:
!>
!> ZSPSV computes the solution to a complex system of linear equations
!> A * X = B,
!> where A is an N-by-N symmetric matrix stored in packed format and X
!> and B are N-by-NRHS matrices.
!>
!> The diagonal pivoting method is used to factor A as
!> A = U * D * U**T, if UPLO = 'U', or
!> A = L * D * L**T, if UPLO = 'L',
!> where U (or L) is a product of permutation and unit upper (lower)
!> triangular matrices, D is symmetric and block diagonal with 1-by-1
!> and 2-by-2 diagonal blocks. The factored form of A is then used to
!> solve the system of equations A * X = B.
!>
so basically: factor A with the diagonal pivoting method, then use that factored form to solve A * X = B. it's giving organized. π
π Parameters
UPLO
!> UPLO is CHARACTER*1
!> = 'U': Upper triangle of A is stored;
!> = 'L': Lower triangle of A is stored.
!>
pick your fighter: 'U' for the upper triangle, 'L' for the lower one. no in-between, bestie. π¦
N
!> N is INTEGER
!> The number of linear equations, i.e., the order of the
!> matrix A. N >= 0.
!>
the number of linear equations β i.e. the order of the matrix A. it must be N >= 0, so no negative chaos allowed. β¨
NRHS
!> NRHS is INTEGER
!> The number of right hand sides, i.e., the number of columns
!> of the matrix B. NRHS >= 0.
!>
how many right hand sides you got, aka how many columns B has. NRHS >= 0. π
AP
!> AP is COMPLEX*16 array, dimension (N*(N+1)/2)
!> On entry, the upper or lower triangle of the symmetric matrix
!> A, packed columnwise in a linear array. The j-th column of A
!> is stored in the array AP as follows:
!> if UPLO = 'U', AP(i + (j-1)*j/2) = A(i,j) for 1<=i<=j;
!> if UPLO = 'L', AP(i + (j-1)*(2n-j)/2) = A(i,j) for j<=i<=n.
!> See below for further details.
!>
!> On exit, the block diagonal matrix D and the multipliers used
!> to obtain the factor U or L from the factorization
!> A = U*D*U**T or A = L*D*L**T as computed by ZSPTRF, stored as
!> a packed triangular matrix in the same storage format as A.
!>
COMPLEX*16 array, dimension (N*(N+1)/2).
On entry: the upper or lower triangle of the symmetric matrix A, packed columnwise in a linear array. The j-th column of A is stored in AP like this:
- if
UPLO = 'U',AP(i + (j-1)*j/2) = A(i,j)for1<=i<=j; - if
UPLO = 'L',AP(i + (j-1)*(2n-j)/2) = A(i,j)forj<=i<=n.
(see below for further details, bestie, there's a whole diagram π)
On exit: the block diagonal matrix D and the multipliers used to obtain the factor U or L from the factorization A = U*D*U**T or A = L*D*L**T as computed by ZSPTRF, stored as a packed triangular matrix in the same storage format as A. it literally stays in the same format, iconic behavior. π
IPIV
!> IPIV is INTEGER array, dimension (N)
!> Details of the interchanges and the block structure of D, as
!> determined by ZSPTRF. If IPIV(k) > 0, then rows and columns
!> k and IPIV(k) were interchanged, and D(k,k) is a 1-by-1
!> diagonal block. If UPLO = 'U' and IPIV(k) = IPIV(k-1) < 0,
!> then rows and columns k-1 and -IPIV(k) were interchanged and
!> D(k-1:k,k-1:k) is a 2-by-2 diagonal block. If UPLO = 'L' and
!> IPIV(k) = IPIV(k+1) < 0, then rows and columns k+1 and
!> -IPIV(k) were interchanged and D(k:k+1,k:k+1) is a 2-by-2
!> diagonal block.
!>
INTEGER array, dimension (N). the details of the interchanges and the block structure of D, as determined by ZSPTRF. read carefully, this is the lore:
- If
IPIV(k) > 0, then rows and columns k andIPIV(k)were interchanged, andD(k,k)is a 1-by-1 diagonal block. - If
UPLO = 'U'andIPIV(k) = IPIV(k-1) < 0, then rows and columns k-1 and-IPIV(k)were interchanged andD(k-1:k,k-1:k)is a 2-by-2 diagonal block. - If
UPLO = 'L'andIPIV(k) = IPIV(k+1) < 0, then rows and columns k+1 and-IPIV(k)were interchanged andD(k:k+1,k:k+1)is a 2-by-2 diagonal block.
yes the negative signs matter. no you cannot skip them. π
B
!> B is COMPLEX*16 array, dimension (LDB,NRHS)
!> On entry, the N-by-NRHS right hand side matrix B.
!> On exit, if INFO = 0, the N-by-NRHS solution matrix X.
!>
COMPLEX*16 array, dimension (LDB,NRHS).
- On entry: the N-by-NRHS right hand side matrix B.
- On exit: if
INFO = 0, the N-by-NRHS solution matrix X. glow up! β¨
LDB
!> LDB is INTEGER
!> The leading dimension of the array B. LDB >= max(1,N).
!>
INTEGER. the leading dimension of the array B, and it must satisfy LDB >= max(1,N). π«Ά
INFO
!> INFO is INTEGER
!> = 0: successful exit
!> < 0: if INFO = -i, the i-th argument had an illegal value
!> > 0: if INFO = i, D(i,i) is exactly zero. The factorization
!> has been completed, but the block diagonal matrix D is
!> exactly singular, so the solution could not be
!> computed.
!>
INTEGER, and it's your vibe check on the whole operation:
= 0: successful exit π< 0: ifINFO = -i, the i-th argument had an illegal value π> 0: ifINFO = i,D(i,i)is exactly zero. The factorization has been completed, but the block diagonal matrix D is exactly singular, so the solution could not be computed. π it did all that work and then couldn't finish. heartbreaking.
π Author
Univ. of Tennessee
Univ. of California Berkeley
Univ. of Colorado Denver
NAG Ltd.
(academic royalty, all of them π)
π¦ Further Details:
!>
!> The packed storage scheme is illustrated by the following example
!> when N = 4, UPLO = 'U':
!>
!> Two-dimensional storage of the symmetric matrix A:
!>
!> a11 a12 a13 a14
!> a22 a23 a24
!> a33 a34 (aij = aji)
!> a44
!>
!> Packed storage of the upper triangle of A:
!>
!> AP = [ a11, a12, a22, a13, a23, a33, a14, a24, a34, a44 ]
!>
ok so here's the visual aid, because reading about packed storage without a picture is lowkey painful. when N = 4, UPLO = 'U':
Two-dimensional storage of the symmetric matrix A:
a11 a12 a13 a14
a22 a23 a24
a33 a34 (aij = aji)
a44
Packed storage of the upper triangle of A:
AP = [ a11, a12, a22, a13, a23, a33, a14, a24, a34, a44 ]
see how it just squishes into one line? that's the whole trick. ate and left no crumbs. π
Definition at line 161 of file zspsv.f.
π Author
Generated automatically by Doxygen for LAPACK from the source code.
and that's the whole page, bestie π«Ά this was LAPACK, Version 3.12.0, live from SRC/zspsv.f(3) β go forth and solve your A * X = B, you've got this ππ
π¦ where this page comes from
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