std::vector::operator[](3)
π NAME π
okay bestie, welcome to the C++ Standard Libary page for std::vector::operator[](3) π
the title is std::vector::operator[](3), and the NAME line is literally:
std::vector::operator[] - std::vector::operator[]
β¨ Synopsis β¨
reference operator[]( size_type pos ); (1) (constexpr
since C++20)
const_reference operator[]( size_type pos ) const; (2) (constexpr
since C++20)
Returns a reference to the element at specified location pos. No bounds checking is performed. π«Ά
no bounds checking, bestie β it's giving raw speed with zero safety net π
π Parameters π
posβ position of the element to return
π¦ Return value π¦
Reference to the requested element. periodt β¨
β‘ Complexity β‘
Constant. O(1) energy, no cap π₯
π§ Notes π§
Unlike std::map::operator[], this operator never inserts a new element into the container. Accessing a nonexistent element through this operator is undefined behavior.
π¨ undefined behavior is not a cute little error message, bestie β it's the scary kind of "anything can happen" π
πΈ Example πΈ
The following code uses operator[] to read from and write to a std::vector<int>:
// Run this code
#include <vector>
#include <iostream>
int main()
{
std::vector<int> numbers{2, 4, 6, 8};
std::cout << "Second element: " << numbers[1] << '\n';
numbers[0] = 5;
std::cout << "All numbers:";
for (auto i : numbers)
std::cout << ' ' << i;
std::cout << '\n';
}
// Since C++20 std::vector can be used in constexpr context:
#if defined(__cpp_lib_constexpr_vector) and defined(__cpp_consteval)
// Gets the sum of all primes in [0, N) using sieve of Eratosthenes
consteval auto sum_of_all_primes_up_to(unsigned N)
{
if (N < 2)
return 0ULL;
std::vector<bool> is_prime(N, true);
is_prime[0] = is_prime[1] = false;
auto propagate_non_primality = [&](decltype(N) n)
{
for (decltype(N) m = n + n; m < is_prime.size(); m += n)
is_prime[m] = false;
};
auto sum{0ULL};
for (decltype(N) n{2}; n != N; ++n)
if (is_prime[n])
{
sum += n;
propagate_non_primality(n);
}
return sum;
} //< vector's memory is released here
static_assert(sum_of_all_primes_up_to(42) == 0xEE);
static_assert(sum_of_all_primes_up_to(100) == 0x424);
static_assert(sum_of_all_primes_up_to(1001) == 76127);
#endif
π Output π
Second element: 4
All numbers: 5 4 6 8
π See also π
atβ access specified element with bounds checking (public member function)
source: http://cppreference.com β’ date: 2024.06.10 β’ page: std::vector::operator[](3) π«Άπ
β¨
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