std::result...nvoke_result(3)

πŸ“¦ version 2024.07.05, in nixpkgs unstable, opensuse-leap 16.0

πŸ’– NAME πŸ’–

okay so bestie, welcome to the <pink>std::result...nvoke_result(3)</pink> page from the <purple>C++ Standard Libary</purple> manual ✨ This one is literally about std::result_of,std::invoke_result β€” yep, that’s the name: std::result_of,std::invoke_result.


✨ Synopsis ✨

Defined in header <type_traits>
template< class >

class result_of; // not defined            (since C++11)
                                           (1) (deprecated in C++17)
template< class F, class... ArgTypes >     (removed in C++20)

class result_of<F(ArgTypes...)>;
template< class F, class... ArgTypes > (2) (since C++17)
class invoke_result;

Okay so the whole point: it deduces the return type of an INVOKE expression at compile time. Literally the compile-time detective πŸ•΅οΈβ€β™€οΈ

F must be a callable type, reference to function, or reference to callable type. (since C++11) Invoking F with ArgTypes... must be a well-formed expression. (until C++14)

F and all types in ArgTypes can be any complete type, array of unknown bound, or (possibly cv-qualified) void. (since C++14)

If the program adds specializations for any of the templates described on this page, the behavior is undefined. πŸ’€

πŸ¦‹ Member types πŸ¦‹

  • type β€” the return type of the Callable type F if invoked with the arguments ArgTypes.... It’s only defined if F can be called with the arguments ArgTypes... in unevaluated context. (since C++14)

πŸŽ€ Helper types πŸŽ€

template< class T >                                            (since C++14)
using result_of_t = typename result_of<T>::type;           (1) (deprecated in C++17)
                                                                         (removed in C++20)
template< class F, class... ArgTypes >
using invoke_result_t = typename invoke_result<F,          (2) (since C++17)
ArgTypes...>::type;

🧚 Possible implementation 🧚

        namespace detail
        {
            template<class T>
            struct is_reference_wrapper : std::false_type {};
            template<class U>
            struct is_reference_wrapper<std::reference_wrapper<U>> :
       std::true_type {};

            template<class T>
            struct invoke_impl
            {
                template<class F, class... Args>
                static auto call(F&& f, Args&&... args)
                    ->
       decltype(std::forward<F>(f)(std::forward<Args>(args)...));
            };

            template<class B, class MT>
            struct invoke_impl<MT B::*>
            {
                template<class T, class Td = typename std::decay<T>::type,
                    class = typename std::enable_if<std::is_base_of<B,
       Td>::value>::type>
                static auto get(T&& t) -> T&&;

                template<class T, class Td = typename std::decay<T>::type,
                    class = typename
       std::enable_if<is_reference_wrapper<Td>::value>::type>
                static auto get(T&& t) -> decltype(t.get());

                template<class T, class Td = typename std::decay<T>::type,
                    class = typename std::enable_if<!std::is_base_of<B,
       Td>::value>::type,
                    class = typename
       std::enable_if<!is_reference_wrapper<Td>::value>::type>
                static auto get(T&& t) -> decltype(*std::forward<T>(t));

                template<class T, class... Args, class MT1,
                    class = typename
       std::enable_if<std::is_function<MT1>::value>::type>
                static auto call(MT1 B::*pmf, T&& t, Args&&... args)
                    -> decltype((invoke_impl::get(
                        std::forward<T>(t)).*pmf)(std::forward<Args>(args)...));

                template<class T>
                static auto call(MT B::*pmd, T&& t)
                    -> decltype(invoke_impl::get(std::forward<T>(t)).*pmd);
            };

            template<class F, class... Args, class Fd = typename
       std::decay<F>::type>
            auto INVOKE(F&& f, Args&&... args)
                -> decltype(invoke_impl<Fd>::call(std::forward<F>(f),
                    std::forward<Args>(args)...));
        } // namespace detail

        // Minimal C++11 implementation:
        template<class> struct result_of;
        template<class F, class... ArgTypes>
        struct result_of<F(ArgTypes...)>
        {
            using type = decltype(detail::INVOKE(std::declval<F>(),
       std::declval<ArgTypes>()...));
        };

        // Conforming C++14 implementation (is also a valid C++11
       implementation):
        namespace detail
        {
            template<typename AlwaysVoid, typename, typename...>
            struct invoke_result {};
            template<typename F, typename...Args>
            struct invoke_result<
                decltype(void(detail::INVOKE(std::declval<F>(),
       std::declval<Args>()...))),
                    F, Args...>
            {
                using type = decltype(detail::INVOKE(std::declval<F>(),
       std::declval<Args>()...));
            };
        } // namespace detail

        template<class> struct result_of;
        template<class F, class... ArgTypes>
        struct result_of<F(ArgTypes...)> : detail::invoke_result<void, F,
       ArgTypes...> {};

        template<class F, class... ArgTypes>
        struct invoke_result : detail::invoke_result<void, F, ArgTypes...> {};

πŸ’€ Notes πŸ’€

As formulated in C++11, the behavior of std::result_of is undefined when INVOKE(std::declval<F>(), std::declval<ArgTypes>()...) is ill-formed (e.g. when F is not a callable type at all). C++14 changes that to a SFINAE (when F is not callable, std::result_of<F(ArgTypes...)> simply doesn't have the type member). 😭

The motivation behind std::result_of is to determine the result of invoking a Callable, in particular if that result type is different for different sets of arguments.

F(Args...) is a function type with Args... being the argument types and F being the return type. As such, std::result_of suffers from several quirks that led to its deprecation in favor of std::invoke_result in C++17:

  • F cannot be a function type or an array type (but can be a reference to them);
  • if any of the Args has type "array of T" or a function type T, it is automatically adjusted to T*;
  • neither F nor any of Args... can be an abstract class type;
  • if any of Args... has a top-level cv-qualifier, it is discarded;
  • none of Args... may be of type void.

To avoid these quirks, result_of is often used with reference types as F and Args.... For example:

        template<class F, class... Args>
        std::result_of_t<F&&(Args&&...)> // instead of
       std::result_of_t<F(Args...)>, which is wrong
            my_invoke(F&& f, Args&&... args)
            {
                /* implementation */
            }

πŸ§ͺ Notes πŸ§ͺ (feature-test macros)

  • __cpp_lib_result_of_sfinae β€” 201210L (C++14) β€” std::result_of and SFINAE
  • __cpp_lib_is_invocable β€” 201703L (C++17) β€” std::is_invocable, std::invoke_result

🌸 Examples 🌸

        // Run this code

        #include <iostream>
        #include <type_traits>

        struct S
        {
            double operator()(char, int&);
            float operator()(int) { return 1.0; }
        };

        template<class T>
        typename std::result_of<T(int)>::type f(T& t)
        {
            std::cout << "overload of f for callable T\n";
            return t(0);
        }

        template<class T, class U>
        int f(U u)
        {
            std::cout << "overload of f for non-callable T\n";
            return u;
        }

        int main()
        {
            // the result of invoking S with char and int& arguments is double
            std::result_of<S(char, int&)>::type d = 3.14; // d has type double
            static_assert(std::is_same<decltype(d), double>::value, "");

            // std::invoke_result uses different syntax (no parentheses)
            std::invoke_result<S,char,int&>::type b = 3.14;
            static_assert(std::is_same<decltype(b), double>::value, "");

            // the result of invoking S with int argument is float
            std::result_of<S(int)>::type x = 3.14; // x has type float
            static_assert(std::is_same<decltype(x), float>::value, "");

            // result_of can be used with a pointer to member function as
       follows
            struct C { double Func(char, int&); };
            std::result_of<decltype(&C::Func)(C, char, int&)>::type g = 3.14;
            static_assert(std::is_same<decltype(g), double>::value, "");

            f<C>(1); // may fail to compile in C++11; calls the non-callable
       overload in C++14
        }

Output:

overload of f for non-callable T

πŸ‘‘ See also πŸ‘‘

  • invoke (C++17), invoke_r (since C++23) β€” invokes any Callable object with given arguments and possibility to specify return type (function template)
  • is_invocable, is_invocable_r, is_nothrow_invocable, is_nothrow_invocable_r (C++17) β€” checks if a type can be invoked (as if by std::invoke) with the given argument types (class template)
  • declval (C++11) β€” obtains a reference to its argument for use in unevaluated context (function template)

And that’s the whole page, bestie πŸ’– source: http://cppreference.com, version/date: 2024.06.10, manual page: std::result...nvoke_result(3) β€” go slay some template metaprogramming 🫢✨

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