std::ranges...view::begin(3)

πŸ“¦ version 2024.07.05, in nixpkgs unstable, opensuse-leap 16.0

πŸ’– NAME πŸ’–

std::ranges...view::begin(3) is the page title, bestie, and it comes from the C++ Standard Libary manual. The NAME line is std::ranges::zip_transform_view::begin - std::ranges::zip_transform_view::begin β€” yes, the same gorgeous mouthful twice. Obsessed. πŸ’…

✨ Synopsis ✨

          constexpr auto begin();                                       (1)
       (since C++23)
          constexpr auto begin() const                                  (2)
       (since C++23)
              requires ranges::range<const ranges::zip_view<Views...>>;

Okay so this member function, begin, does one job: Obtains the beginning iterator of zip_transform_view. Main character energy fr fr. πŸ”₯

  1. This overload is equivalent to return /*iterator*/<false>(*this, zip_.begin());.
  2. This overload is equivalent to return /*iterator*/<true>(*this, zip_.begin());.

πŸŽ€ Parameters πŸŽ€

(none) β€” literally no parameters, bestie. The vibe check is empty and that's valid. πŸ’–

🌸 Return value 🌸

Iterator to the first element. That's it. No cap. πŸ¦‹

πŸ’« Notes πŸ’«

ranges::range<const ranges::zip_view<Views...>> is modeled if and only if for every type Vi in Views..., const Vi models range. So that's the little condition doing the heavy lifting. Periodt. πŸ’…

🧚 Example 🧚

This section is incomplete Reason: no example

Not me leaving the example section empty, but that's what the page says, bestie. πŸ™ˆ

πŸ‘‘ See also πŸ‘‘

  • end β€” returns an iterator or a sentinel to the end (C++23) (public member function) ✨
  • ranges::begin β€” returns an iterator to the beginning of a range (C++20) (customization point object) 🌈

πŸ“ Category πŸ“

  • * Todo no example

Catch you later, bestie! This page is from http://cppreference.com and carries the date 2024.06.10. Go slay some ranges. πŸ’–πŸ«Άβœ¨

πŸ“¦ where this page comes from