std::ranges...ward_result(3)

πŸ“¦ version 2024.07.05, in nixpkgs unstable, opensuse-leap 16.0

πŸ’… std::ranges::move_backward, std::ranges::move_backward_result πŸ’…

okay so bestie, we're in the C++ Standard Libary manual, page std::ranges...ward_result(3) ✨ and this is the whole glow-up on std::ranges::move_backward plus its helper std::ranges::move_backward_result πŸ’–.

✨ NAME ✨

std::ranges::move_backward,std::ranges::move_backward_result β€” literally the page for std::ranges::move_backward and std::ranges::move_backward_result, no cap. πŸ‘‘

🌸 Synopsis 🌸

          Defined in header <algorithm>
          Call signature
          template< std::bidirectional_iterator I1, std::sentinel_for<I1> S1,

                    std::bidirectional_iterator I2 >
       (since
          requires std::indirectly_movable<I1, I2>
       (1) C++20)
          constexpr move_backward_result<I1, I2>

              move_backward( I1 first, S1 last, I2 result );
          template< ranges::bidirectional_range R, std::bidirectional_iterator
       I >

          requires std::indirectly_movable<ranges::iterator_t<R>, I>
       (2) (since
          constexpr move_backward_result<ranges::borrowed_iterator_t<R>, I>
       C++20)

              move_backward( R&& r, I result );

πŸŽ€ Helper types πŸŽ€

          template< class I, class O >
       (3) (since
          using move_backward_result = ranges::in_out_result<I, O>;
       C++20)

so like, (1) is the iterator-pair version, (2) is the range version, and (3) is the helper alias move_backward_result β€” all of them are living that since C++20 life πŸ’….

  1. Moves the elements in the range, defined by [first, last), to another range [result - N, result), where N = ranges::distance(first, last). The elements are moved in reverse order (the last element is moved first), but their relative order is preserved. The behavior is undefined if result is within (first, last]. In such a case, ranges::move may be used instead.
⚠️ real talk: the behavior is undefined if result is within (first, last]. In such a case, ranges::move may be used instead. do not play with UB bestie 😭
  1. Same as (1), but uses r as the source range, as if using ranges::begin(r) as first, and ranges::end(r) as last.

The elements in the moved-from range will still contain valid values of the appropriate type, but not necessarily the same values as before the move, as if using *(result - n) = ranges::iter_move(last - n) for each integer n, where 0 ≀ n < N.

The function-like entities described on this page are niebloids, that is:

  • Explicit template argument lists cannot be specified when calling any of them.
  • None of them are visible to argument-dependent lookup.
  • When any of them are found by normal unqualified lookup as the name to the left of the function-call operator, argument-dependent lookup is inhibited.

In practice, they may be implemented as function objects, or with special compiler extensions.

🫢 Parameters 🫢

  • first β€” the beginning of the range of elements to move.
  • last β€” the end of the range of elements to move.
  • r β€” the range of the elements to move.
  • result β€” the end of the destination range.

πŸŽ€ Return value πŸŽ€

{last, result - N}. that's the whole return vibe πŸ’….

πŸ”₯ Complexity πŸ”₯

  1. Exactly N move assignments.
  2. Exactly ranges::distance(r) move assignments.

πŸ¦‹ Notes πŸ¦‹

When moving overlapping ranges, ranges::move is appropriate when moving to the left (beginning of the destination range is outside the source range) while ranges::move_backward is appropriate when moving to the right (end of the destination range is outside the source range).

πŸ’œ Possible implementation πŸ’œ

          struct move_backward_fn
          {
              template<std::bidirectional_iterator I1, std::sentinel_for<I1>
       S1,
                       std::bidirectional_iterator I2>
              requires std::indirectly_movable<I1, I2>
              constexpr ranges::move_backward_result<I1, I2>
                  operator()(I1 first, S1 last, I2 result) const
              {
                  auto i {last};
                  for (; i != first; *--result = ranges::iter_move(--i))
                  {}
                  return {std::move(last), std::move(result)};
              }

              template<ranges::bidirectional_range R,
       std::bidirectional_iterator I>
              requires std::indirectly_movable<ranges::iterator_t<R>, I>
              constexpr
       ranges::move_backward_result<ranges::borrowed_iterator_t<R>, I>
                  operator()(R&& r, I result) const
              {
                  return (*this)(ranges::begin(r), ranges::end(r),
       std::move(result));
              }
          };

          inline constexpr move_backward_fn move_backward {};

🌈 Example 🌈

       // Run this code

        #include <algorithm>
        #include <iostream>
        #include <string>
        #include <string_view>
        #include <vector>

        using Vec = std::vector<std::string>;

        void print(std::string_view rem, Vec const& vec)
        {
            std::cout << rem << "[" << vec.size() << "]: ";
            for (const std::string& s : vec)
                std::cout << (s.size() ? s : std::string{"Β·"}) << ' ';
            std::cout << '\n';
        }

        int main()
        {
            Vec a{"▁", "β–‚", "β–ƒ", "β–„", "β–…", "β–†", "β–‡", "β–ˆ"};
            Vec b(a.size());

            print("Before move:\n" "a", a);
            print("b", b);

            std::ranges::move_backward(a, b.end());

            print("\n" "Move a >> b:\n" "a", a);
            print("b", b);

            std::ranges::move_backward(b.begin(), b.end(), a.end());
            print("\n" "Move b >> a:\n" "a", a);
            print("b", b);

            std::ranges::move_backward(a.begin(), a.begin()+3, a.end());
            print("\n" "Overlapping move a[0, 3) >> a[5, 8):\n" "a", a);
        }

⭐ Possible output ⭐

    Before move:
    a[8]: ▁ β–‚ β–ƒ β–„ β–… β–† β–‡ β–ˆ
    b[8]: Β· Β· Β· Β· Β· Β· Β· Β·

    Move a >> b:
    a[8]: Β· Β· Β· Β· Β· Β· Β· Β·
    b[8]: ▁ β–‚ β–ƒ β–„ β–… β–† β–‡ β–ˆ

    Move b >> a:
    a[8]: ▁ β–‚ β–ƒ β–„ β–… β–† β–‡ β–ˆ
    b[8]: Β· Β· Β· Β· Β· Β· Β· Β·

    Overlapping move a[0, 3) >> a[5, 8):
    a[8]: Β· Β· Β· β–„ β–… ▁ β–‚ β–ƒ

πŸ‘‘ See also πŸ‘‘

  • ranges::move β€” moves a range of elements to a new location (C++20) (niebloid)
  • ranges::copy, ranges::copy_if β€” copies a range of elements to a new location (C++20) (niebloid) (C++20)
  • ranges::copy_backward β€” copies a range of elements in backwards order (C++20) (niebloid)
  • move β€” moves a range of elements to a new location (C++11) (function template)
  • move β€” obtains an rvalue reference (C++11) (function template)

sending u a kiss πŸ’– β€” source http://cppreference.com, version/date 2024.06.10, page std::ranges...ward_result(3). byeee bestie πŸŽ€βœ¨

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