std::ranges...ment_result(3)
π NAME π
std::ranges::minmax_element,std::ranges::minmax_element_result
okay so this page is from the C++ Standard Library manual β and yes, the header literally says βC++ Standard Libaryβ, we are not fixing it, itβs iconic. Itβs all about the std::ranges::minmax_element and std::ranges::minmax_element_result duo. itβs giving algorithm bestie energy: smallest and largest, handled. no cap π
β¨ Synopsis β¨
okay so the synopsis is a little cursed with line wrapping, but hereβs the exact thing, every token intact:
Defined in header <algorithm>
Call signature
template< std::forward_iterator I, std::sentinel_for<I> S, class Proj
=
std::identity,
std::indirect_strict_weak_order<std::projected<I, Proj>>
Comp (1) (since
= ranges::less >
C++20)
constexpr minmax_element_result<I>
minmax_element( I first, S last, Comp comp = {}, Proj proj = {}
);
template< ranges::forward_range R, class Proj = std::identity,
std::indirect_strict_weak_order<
std::projected<ranges::iterator_t<R>, Proj>> Comp =
(2) (since
ranges::less >
C++20)
constexpr minmax_element_result<ranges::borrowed_iterator_t<R>>
minmax_element( R&& r, Comp comp = {}, Proj proj = {} );
Helper types
template< class I >
(3) (since
using minmax_element_result = ranges::min_max_result<I>;
C++20)
- Finds the smallest and largest elements in the range
[first, last). - Same as (1), but uses
ras the source range, as if usingranges::begin(r)asfirstandranges::end(r)aslast.
The function-like entities described on this page are niebloids, that is:
- Explicit template argument lists cannot be specified when calling any of them.
- None of them are visible to argument-dependent lookup.
- When any of them are found by normal unqualified lookup as the name to the left of the function-call operator, argument-dependent lookup is inhibited.
In practice, they may be implemented as function objects, or with special compiler extensions. iykyk, niebloid life π
πΈ Parameters πΈ
first,lastβ the iterator-sentinel pair that marks the range youβre examining. literally the start/end-ish combo for the range to examine.rβ the range to examine. same energy, but as a whole range object.compβ the comparison you want applied to the projected elements.projβ the projection you want applied to the elements.
π Return value π
You get an object with two iterators inside: the first one points at the smallest element, and the second one points at the greatest element. If the range is empty, you get {first, first}. If several elements are equivalent to the smallest element, you get the iterator to the first such element. If several elements are equivalent to the largest element, you get the iterator to the last such element. periodt π«Ά
π₯ Complexity π₯
At most std::max(std::floor(1.5 * (N β 1)), 0.0) applications of the comparison, and twice as many applications of the projection, where N = ranges::distance(first, last). thatβs the whole budget, bestie. no extra π
π§ Possible implementation π§
hereβs the possible implementation, copied exactly because we do not mess with code:
struct minmax_element_fn {
template<std::forward_iterator I, std::sentinel_for<I> S, class Proj
= std::identity,
std::indirect_strict_weak_order<std::projected<I, Proj>>
Comp = ranges::less>
constexpr ranges::minmax_element_result<I>
operator()(I first, S last, Comp comp = {}, Proj proj = {})
const
{
auto min = first, max = first;
if (first == last || ++first == last)
return {min, max};
if (std::invoke(comp, std::invoke(proj, *first),
std::invoke(proj, *min)))
min = first;
else
max = first;
while (++first != last)
{
auto i = first;
if (++first == last)
{
if (std::invoke(comp, std::invoke(proj, *i),
std::invoke(proj, *min)))
min = i;
else if (!(std::invoke(comp, std::invoke(proj, *i),
std::invoke(proj, *max))))
max = i;
break;
}
else
{
if (std::invoke(comp, std::invoke(proj, *first),
std::invoke(proj, *i)))
{
if (std::invoke(comp, std::invoke(proj, *first),
std::invoke(proj, *min)))
min = first;
if (!(std::invoke(comp, std::invoke(proj, *i),
std::invoke(proj, *max))))
max = i;
}
else
{
if (std::invoke(comp, std::invoke(proj, *i),
std::invoke(proj, *min)))
min = i;
if (!(std::invoke(comp, std::invoke(proj, *first),
std::invoke(proj, *max))))
max = first;
}
}
}
return {min, max};
}
template<ranges::forward_range R, class Proj = std::identity,
std::indirect_strict_weak_order<
std::projected<ranges::iterator_t<R>, Proj>> Comp =
ranges::less>
constexpr
ranges::minmax_element_result<ranges::borrowed_iterator_t<R>>
operator()(R&& r, Comp comp = {}, Proj proj = {}) const
{
return (*this)(ranges::begin(r), ranges::end(r), std::ref(comp),
std::ref(proj));
} };
inline constexpr minmax_element_fn minmax_element;
π Example π
#include <algorithm>
#include <iostream>
#include <iterator>
namespace ranges = std::ranges;
int main()
{
const auto v = {3, 9, 1, 4, 1, 2, 5, 9};
const auto [min, max] = ranges::minmax_element(v);
std::cout
<< "min = " << *min << ", at [" << ranges::distance(v.begin(),
min) << "]\n"
<< "max = " << *max << ", at [" << ranges::distance(v.begin(),
max) << "]\n";
}
π Output π
min = 1, at [2]
max = 9, at [7]
π See also π
ranges::min_elementβ returns the smallest element in a range. (C++20) (niebloid)ranges::max_elementβ returns the largest element in a range. (C++20) (niebloid)ranges::minmaxβ returns the smaller and larger of two elements. (C++20) (niebloid)minmax_elementβ returns the smallest and the largest elements in a range. (C++11) (function template)
source: cppreference.com Β· date: 2024.06.10 Β· page: std::ranges...ment_result(3) β mwah, go slay some ranges bestie πβ¨
π¦ where this page comes from
- nixpkgs unstable: stdman 2024.07.05
- opensuse-leap 16.0: stdman 2024.07.05-bp160.1.9 Β· MIT
- π girlified by deepseek-ai/DeepSeek-V4.1-Flash-1017 on : a language model's rewrite of the original, under its terms