std::experi...conjunction(3)
π NAME π
Welcome to the std::experi...conjunction(3) page from the C++ Standard Libary β yes bestie, that spelling is in the source, I'm not fixing it π
.
std::experimental::conjunction β std::experimental::conjunction.
πΈ SYNOPSIS πΈ
Defined in header <experimental/type_traits>:
template< class... B > (library fundamentals TS v2)
struct conjunction;
Okay so this forms the logical conjunction of the type traits B..., effectively performing a logical AND on the sequence of traits. No cap.
The specialization std::experimental::conjunction<B1, ..., BN> has a public and unambiguous base that is:
- if
sizeof...(B) == 0,std::true_type; otherwise - the first type
BiinB1, ..., BNfor whichbool(Bi::value) == false, orBNif there is no such type.
The member names of the base class, other than conjunction and operator=, are not hidden and are unambiguously available in conjunction.
Conjunction is short-circuiting: if there is a template type argument Bi with bool(Bi::value) == false, then instantiating conjunction<B1, ..., BN>::value does not require the instantiation of Bj::value for j > i.
π TEMPLATE PARAMETERS π
B...β every template argumentBifor whichBi::valueis instantiated must be usable as a base class and define membervaluethat is convertible tobool.
π¦ HELPER VARIABLE TEMPLATE π¦
template< class... B >
constexpr bool conjunction_v = (library fundamentals TS v2)
conjunction<B...>::value;
π₯ POSSIBLE IMPLEMENTATION π₯
template<class...> struct conjunction : std::true_type {};
template<class B1> struct conjunction<B1> : B1 {};
template<class B1, class... Bn>
struct conjunction<B1, Bn...>
: std::conditional_t<bool(B1::value), conjunction<Bn...>, B1> {};
π NOTES π
A specialization of conjunction does not necessarily inherit from either std::true_type or std::false_type: it simply inherits from the first B whose ::value, converted to bool, is false, or from the very last B when all of them convert to true. For example, conjunction<std::integral_constant<int, 2>, std::integral_constant<int, 4>>::value is 4. Wild, right? π
π EXAMPLE π
// Run this code
#include <experimental/type_traits>
#include <iostream>
// func is enabled if all Ts... have the same type
template<typename T, typename... Ts>
constexpr
std::enable_if_t<std::experimental::conjunction_v<std::is_same<T,
Ts>...>>
func(T, Ts...)
{
std::cout << "All types are the same.\n";
}
template<typename T, typename... Ts>
constexpr
std::enable_if_t<!std::experimental::conjunction_v<std::is_same<T,
Ts>...>>
func(T, Ts...)
{
std::cout << "Types differ.\n";
}
int main()
{
func(1, 2'7, 3'1);
func(1, 2.7, '3');
}
β OUTPUT β
All types are the same.
Types differ.
π SEE ALSO π
conjunctionβ variadic logical AND metafunction,(C++17)(class template).
okay that's the whole page, bestie π«Ά β source/version/date: http://cppreference.com Β· 2024.06.10 Β· std::experi...conjunction(3). slay and bye β¨
π¦ where this page comes from
- nixpkgs unstable: stdman 2024.07.05
- opensuse-leap 16.0: stdman 2024.07.05-bp160.1.9 Β· MIT
- π girlified by deepseek-ai/DeepSeek-V4.1-Flash-1017 on : a language model's rewrite of the original, under its terms