SRC/dsptrf.f(3)
SRC/dsptrf.f(3) π β from the Library Functions Manual, bestie
Okay so this is the DSPTRF page, and itβs giving LAPACK main character energy. Weβre keeping every single detail, no cap. π
NAME β¨
SRC/dsptrf.f β literally the name, bestie. This is the page for the DSPTRF routine, and weβre about to go through it like the responsible Unix bestie I am. π«Ά
SYNOPSIS π¦
Functions/Subroutines π§©
subroutine dsptrf (uplo, n, ap, ipiv, info)
DSPTRF
Function/Subroutine Documentation πΈ
Hereβs the full signature, copied exactly because we do not mess with code, periodt:
subroutine dsptrf (character uplo, integer n, double precision, dimension( *
) ap, integer, dimension( * ) ipiv, integer info)
DSPTRF
Purpose π―
DSPTRF computes the factorization of a real symmetric matrix A stored in packed format using the Bunch-Kaufman diagonal pivoting method:
A = U*D*U**T or A = L*D*L**T
where U (or L) is a product of permutation and unit upper (lower) triangular matrices, and D is symmetric and block diagonal with 1-by-1 and 2-by-2 diagonal blocks.
Parameters π
Okay bestie, parameters time β every one of them, in order, no skipping:
UPLO π¦
UPLO is CHARACTER*1.
= 'U': Upper triangle of A is stored;= 'L': Lower triangle of A is stored.
N πΈ
N is INTEGER.
The order of the matrix A. N >= 0.
AP π
AP is DOUBLE PRECISION array, dimension (N*(N+1)/2).
On entry, the upper or lower triangle of the symmetric matrix A, packed columnwise in a linear array. The j-th column of A is stored in the array AP as follows:
- if
UPLO = 'U',AP(i + (j-1)*j/2) = A(i,j)for1<=i<=j; - if
UPLO = 'L',AP(i + (j-1)*(2n-j)/2) = A(i,j)forj<=i<=n.
On exit, the block diagonal matrix D and the multipliers used to obtain the factor U or L, stored as a packed triangular matrix overwriting A (see below for further details).
IPIV π₯
IPIV is INTEGER array, dimension (N).
Details of the interchanges and the block structure of D.
- If
IPIV(k) > 0, then rows and columns k andIPIV(k)were interchanged andD(k,k)is a 1-by-1 diagonal block. - If
UPLO = 'U'andIPIV(k) = IPIV(k-1) < 0, then rows and columns k-1 and-IPIV(k)were interchanged andD(k-1:k,k-1:k)is a 2-by-2 diagonal block. - If
UPLO = 'L'andIPIV(k) = IPIV(k+1) < 0, then rows and columns k+1 and-IPIV(k)were interchanged andD(k:k+1,k:k+1)is a 2-by-2 diagonal block.
INFO π
INFO is INTEGER.
= 0: successful exit< 0: ifINFO = -i, the i-th argument had an illegal value> 0: ifINFO = i,D(i,i)is exactly zero. The factorization has been completed, but the block diagonal matrix D is exactly singular, and division by zero will occur if it is used to solve a system of equations.
Author π«Ά
Shoutout to the authors, bestie:
- Univ. of Tennessee
- Univ. of California Berkeley
- Univ. of Colorado Denver
- NAG Ltd.
Further Details π
Okay this part is the deep lore, and itβs lowkey iconic. If UPLO = 'U', then A = U*D*U**T, where
U = P(n)*U(n)* ... *P(k)U(k)* ...,
i.e., U is a product of terms P(k)*U(k), where k decreases from n to 1 in steps of 1 or 2, and D is a block diagonal matrix with 1-by-1 and 2-by-2 diagonal blocks D(k). P(k) is a permutation matrix as defined by IPIV(k), and U(k) is a unit upper triangular matrix, such that if the diagonal block D(k) is of order s (s = 1 or 2), then
( I v 0 ) k-s
U(k) = ( 0 I 0 ) s
( 0 0 I ) n-k
k-s s n-k
- If
s = 1,D(k)overwritesA(k,k), and v overwritesA(1:k-1,k). - If
s = 2, the upper triangle ofD(k)overwritesA(k-1,k-1),A(k-1,k), andA(k,k), and v overwritesA(1:k-2,k-1:k).
If UPLO = 'L', then A = L*D*L**T, where
L = P(1)*L(1)* ... *P(k)*L(k)* ...,
i.e., L is a product of terms P(k)*L(k), where k increases from 1 to n in steps of 1 or 2, and D is a block diagonal matrix with 1-by-1 and 2-by-2 diagonal blocks D(k). P(k) is a permutation matrix as defined by IPIV(k), and L(k) is a unit lower triangular matrix, such that if the diagonal block D(k) is of order s (s = 1 or 2), then
( I 0 0 ) k-1
L(k) = ( 0 I 0 ) s
( 0 v I ) n-k-s+1
k-1 s n-k-s+1
- If
s = 1,D(k)overwritesA(k,k), and v overwritesA(k+1:n,k). - If
s = 2, the lower triangle ofD(k)overwritesA(k,k),A(k+1,k), andA(k+1,k+1), and v overwritesA(k+2:n,k:k+1).
Contributors π§
J. Lewis, Boeing Computer Services Company β thank you for your service, icon. π
π Definition at line 158 of file dsptrf.f.
Author (the generator one) π»
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